
Timothy A. answered 05/17/16
Tutor
4.9
(75)
I am here to raise mathematicians.
(30/100i-75)x(10-6i/6i-8)
=(6/20i-15)x(5-3i/3i-4)
=(6)(5-3i)/(3i-4)(20i-15)
=(30-18i)/(-60-80i-45i+60)
=(30-18i)/(-125i)
(4-2i)/(-10+5i)x(3-i)/(-3+i)
=(4-2i)/(-10+5i)x(-1)
=(-4+2i)/(10-5i)
=2(-2+i)/5(2-i)
=-2/5