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on a standard coordinate plane, what is the distance between the two points(8,4) (5,-2)

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2 Answers

The distance of two points is: d = √[(X- X1)2 + (Y2 - Y1)2]
 
So, for your problem, X1 = 8, Y1 = 4, X2 = 5, Y2 = -2
 
Just plug those numbers into the formula:
 
d = √[(5 - 8)2 + (-2 - 4)2]
d = √[(-3)2 + (-6)2]
d = √[9 + 36]
d = √[45]
d = 3√[5]
OR
d = 6.708
Use the distance formula
 
x2 = 8
x1 = 5
 
y2 = 4
y1 = -2
 
Sqrt(    (x2 - x1)2 +  (y2 - y1)2    )
 
Sqrt(        (8 - 5 )2   + (4 - (-2))2      )
 
Sqrt( 32 + 6)
 
sqrt (9 + 36)
 
sqrt(45)
 
sqrt(9) * sqrt(5)
 
3 sqrt(5) or 3√5