on a standard coordinate plane, what is the distance between the two points(8,4) (5,-2)

The distance of two points is: d = √[(X

_{2 }- X_{1})^{2}+ (Y_{2}- Y_{1})^{2}]So, for your problem, X

_{1}= 8, Y_{1}= 4, X_{2}= 5, Y_{2}= -2Just plug those numbers into the formula:

d = √[(5 - 8)

^{2}+ (-2 - 4)^{2}]_{ }d = √[(-3)

^{2}+ (-6)^{2}]d = √[9 + 36]

d = √[45]

d = 3√[5]

OR

d = 6.708