on a standard coordinate plane, what is the distance between the two points(8,4) (5,-2)

Question

on a standard coordinate plane, what is the distance between the two points(8,4)  (5,-2)

Answer 1

The distance of two points is: d = √[(X₂ - X₁)² + (Y₂ - Y₁)²]

 

So, for your problem, X₁ = 8, Y₁ = 4, X₂ = 5, Y₂ = -2

 

Just plug those numbers into the formula:

 

d = √[(5 - 8)² + (-2 - 4)²]

d = √[(-3)² + (-6)²]

d = √[9 + 36]

d = √[45]

d = 3√[5]

OR

d = 6.708

Answer 2

Use the distance formula

 

x₂ = 8

x₁ = 5

 

y₂ = 4

y₁ = -2

 

Sqrt(    (x₂ - x₁)² +  (y₂ - y₁)²    )

 

Sqrt(        (8 - 5 )²   + (4 - (-2))²      )

 

Sqrt( 3² + 6² )

 

sqrt (9 + 36)

 

sqrt(45)

 

sqrt(9) * sqrt(5)

 

3 sqrt(5) or 3√5