Roman C. answered 05/09/16
Tutor
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Masters of Education Graduate with Mathematics Expertise
1/x + 4/(x2 - 1) = 2/(x2 - x)
(x2 - 1)/[x(x2 - 1)] + 4x/[x(x2 - 1)] = 2/(x2 - x)
(x2 + 4x - 1)/[x(x2 - 1)] = 2/(x2 - x)
(x2 + 4x - 1)(x2 - x) = 2x(x2 - 1)
x4 + 3x3 - 5x2 + x = 2x3 - 2x
x4 + x3 - 5x2 + 3x = 0
x(x - 1)2(x + 3) = 0
However, from the original equation, we see that x ≠ 0 and x ≠ 1.
So the only solution is x = -3.