The median of a set of data may or may not be value in the set?

Question

It is about math and that is basicall it for now

Answer 1

if the number of numbers in the data set is odd (e.g., 5), then the median will be a value on the data set --- example:

2, 5, 8, 9, 10 --- the median is the middle number, i.e., 8, which is a number in the data set --- if, on the other hand, the number of numbers in the data set is even (e.g, 6, then the median will be the average of the two middle numbers, which may or may not be in the data set --- example:  2, 5, 6, 7, 8, 9 --- the median is the average of 6 and 7, i.e., (6 + 7)/2 = 6.5 ------ example: 2, 5, 6, 6, 7, 8 ------the median is the average of 6 and 6, i.e., (6 + 6)/2 = 6

Answer 2

There are three main ways to find the average of a number set: mean, median, and mode

mean = the total average of all the numbers

median = the number that sit in the middle of the set

mode = the number that crops up the most often

 

With the median, when there is an even number in the set, you take the two numbers in the middle, add them together, and divide by 2:

3, 6, 10, 18

6 + 10 = 16

16 / 2 = 8

As you can see, this number is not part of the set.

 

5, 8, 10, 10, 18, 19

10 + 10 = 20

20 / 2 = 10

In this case, 10 is part of the set.

 

In an odd number in the set, we look at the number directly in the middle:

9, 12, 14, 17, 20

14 is in the middle, and is part of the set.

 

So the statement is true: when dealing with the median, the number indeed may or may not be a value in the set.

Answer 3

The median of a set is considered to be the middle value when the set is listed in numerical order. IF the set has an even number of elements, the median is defined as the average of the middle pair, which may not be a value included in the set. Forex:

 

{1,2,4,5,6} has a median of 4.

 

{1,3,4,6} has no single center, so the median is defined as the average of 3 and 4, or 3.5.