Characteristic

Question

In the nuclear equation

 

222                    4    He +

                          2

Rn→ 

 86

The characteristics of the missing particle are (3 points)

Z = 84, A = 220

Z = 88, A = 218

Z = 84, A = 218

Z = 85, A = 220

Answer 1

Both A and Z must be conserved.

222 = 4 + A

A = 218

86 = 2 + Z

Z = 84