Arthur D. answered 02/18/16
Tutor
4.9
(306)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
distance=rate*time
d=rt
32=rt -------------> 32/r=t
10=(r+5)(2-t)
substitute
10=(r+5)(2-[32/r])
10=2r+5*2-[32/r]r-5[32/r]
10=2r+10-32-160/r
10=2r-22-160/r
10r=2r^2-22r-160
2r^2-22r-10r-160=0
2r^2-32r-160=0
r^2-16r-80=0
factor
(r-20)(r+4)=0
r-20=0
r=20 mph in the foothills (answer)