
Kenneth S. answered 02/17/16
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
the dimensions of each label are 4/3 in by 9/4 in.
I. Consider placing the labels side by side running across the paper width, 9 inches. how many? n(4/3) ≤ 9; so maximum n = 6.75, rounded down to 6 (no partial labels allowed).
Going down the length (12"), there are m rows of labels; m(9/4) ≤ 12 so m maximum = 48/9 = 5.333; maximum m is 5.
Thus 6 times 5 = 30 labels, in this option.
II. Placing labels along the paper length, 12". n(4/3) ≤ 12; n ≤ (3/4)(12) = 9
Going down (9"), m (9/4) ≤ 9; maximum m = 4. Thus 4 times 9 = 36 labels, in this option.
Final answer: 36