Benjamin G. answered 02/11/16
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Let Q & D be the number of quarters and dimes, respectively. Then we can write two equations, for the total number of coins, and for the total value in cents:
Q + D = 24
25Q + 10D = 390
Dividing the second equation by 5, we get
5Q + 2D = 78.
Multiplying the first equation by 2, we have
2Q + 2D = 48.
Subtracting these, we find
3Q = 30
or Q=10, which, when subsituting in the last equation, we can use to find D:
2(10) + 2D = 48
20 + 2D = 48
10 + D = 24 (dividing by 2, or 2D=28 subtracting 20)
D = 14.
So there are 10 quarters and 14 dimes.
This is a uniquely determined solution since we had two (non-equivalent) equations in two unknowns (that was solvable).