Solve y less than or equal to 2/3x + 4

Question

Its talking about algebra 1 and linear inequality.

Answer 1

Examine the given relation   y ≤ (3/4)x + 4 by 4 -- considering it as an equation, TEMPORARILY. 

 

That's a straight line having y intercept 4 and x-intercept -16/3 (you get this by solving (3/4)x + 4 = 0. 

 

Draw that line as a solid line, because the inequality includes = as well as <. 

 

The solution set is ALL POINTS ON OR BELOW THIS LINE.

 

If the inequality had been only < then you'd draw the boundary line as ------

If the inequality had been > then your solution would be all points ABOVE the boundary line.

 

The key to all such linear inequality problems is to "solve for y" so that you determine the boundary line; LESS means below, GREATER means above.