chris leaves his house by car at 3 p.m., and Joyce leaves his house by car at 5 p.m. their houses are 540 km apart from each other. what time will they meet?

Question

Chris travels 50 km in 1 hour, and Joyce traveks 60 km in 1 hour.

Answer 1

50(x+2) + 60x = 540

110x = 440

 

x = 4

 

they will meet 4 hours after 5pm or at 9pm

Answer 2

Do this problem in stages.

 

The first stage is to find out where Chris is after 2 hours.

 

Assuming Chris and Joyce will be driving toward each other once Joyce gets on the road,

 

Chris is (50 kph)(2 hrs) = 100 km closer to Joyce's house, and it's 5 p.m.

 

 

The second stage is to solve the problem when they're only 440 km apart.

 

Let the time until meeting be t.

 

Chris's distance is 50t, his rate times t.

 

Joyce's distance is 60t.

 

The sum of these distances is 440 km.

 

50t + 60t = 440

 

110t = 440

 

t = 4.

 

The meeting takes place 4 hours after 5 p.m.:  9 p.m.