this is solve for x can anyone out there help me please

What if the problem is really 2^(x+2)+2^(x+1)=192 ?

If this is the case we have (2^x)(2^2)+(2^x)(2^1)=192

(2^x)4+(2^x)2=192

6(2^x)=192

2^x=32

x=5(we don't need logs because we know 32 is a power of 2)

check: (2^7)+(2^6)=128+64=192