what is an equation of the line that passes through the points (3,-3) and (-3,-3) ?

Question

algebra problem, equation

Answer 1

Since it is a line, you can either use a formula (where the slope will be 0) or you can just write:   y=-3

Answer 2

what is an equation of the line that passes through the points (3,-3) and (-3,-3) ?

 

In general to solve a problem of this type you can use the point-slope form of a line:

                     y - yo = m(x - xo)

where

       m = (y2 - y1)/(x2 - x1)

So:

Let

(3,-3) be point 1

and

(-3,-3) be point 2

 

Then m = (-3 - -3)/(-3 - 3)

            = (-3 + 3)/ (-6)

            = 0/6

            = 0

            ==> slope of zero

            ==> horizontal line.

so y - yo = m(x - xo)

            ==> y - yo = 0

            ==> y = yo

            ==> y = -3 is your equation for this particular problem.

Answer 3

Both points have the same y-coordinate, -3.

A line through those two points would be a vertical line.

Each point on that line would have a y-coordinate of -3.

So the equation of the line is y = -3.