These are composite functions and are worked from the inside out.
The first thing we have to recall is that (f º g) (5) = f(g(5))
Now with f(g(5)), you have to first recognize that x=5. Using that solve for g(5). You would then take that answer and use it as your x for the f(x).
So g(x) = √(3x) = √[(3)(5)] = √(15)
f(x) = x3 + 6x
Solve for f(x) where x = √(15).
Now with f(g(5)), you have to first recognize that x=5. Using that solve for g(5). You would then take that answer and use it as your x for the f(x).
So g(x) = √(3x) = √[(3)(5)] = √(15)
f(x) = x3 + 6x
Solve for f(x) where x = √(15).
f(√(15)) = [√(15)]3 + 6 (√(15))
[√(15)]3 = {[√(15)]2}{[√(15)]} = 15 √(15)
We have 15 √(15) + 6 √(15) = 25 √(15)
So f(g(5)) = 25 √(15).
I hope this helps.
So f(g(5)) = 25 √(15).
I hope this helps.