A chemist has a 25% and a 50% acid solution. How much should be used to form 200 mL of a 35% acid solution?

Question

i need help with my home work

Answer 1

Let there be x ml 25% acid and (200 - x) ml 50% acid.

0.25x+0.5(200-x) = 200*0.35

0.25x +100 -0.5x = 70

30 = 0.25x

x=120

 

200 -x =200 -120 =80

so 120ml 25% acid and 80 ml 50% acid.