Susan C. answered 11/22/15
Tutor
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(31)
I love math, and I love to teach it.
Dear Karen,
Question: What is May's speed in still water?
Let "X=speed in still water"
.___20Km____> upstream Note: distance1=distance2 d=r*time and t=d/rate
<__20Km ____. downstream total time=5 hours time upstream + time downstream =total time
Now, make a table for all the above data:
d = r * t= d/r____________________
20 km X+3 20 km/ X+3 upstream travel
20 km X-3 20 km/ X-3 downstream travel
5 hours total time
upstream time + downstream time = total time Use substitution.
20/ (X+3) + 20/(X-3) = 5 You need a common factor to multiply each term by in order to get
rid of the fractions. Multiply (X+3) by (x-3), and you got the common factors. Use this for each term.
(X+3)(X-3) 20/(X+3) + 20/ (X-3) (X+3)(X-3)= 5 (X+3)(X-3) Simplify by canceling like factors
20(X-3) + 20 (X+3) = 5 (X2 +3X -3X-9)=5(X2-9)
20X-60 + 20X+60 = 5X2 -45 The +60 and -60 cancel each other out.
40X=5X2-45 Simplify by writing equation in standard quadratic form.
0= 5X2 +40X -45 Simplify by dividing every term by 5.
0= 5X2 +40X -45 Simplify by dividing every term by 5.
0= X2 + 8X-9 Factor, but use only a positive answer for X.
0=( )( )
X= _____km/1hour=speed of still water Answer
If I have helped you, please give me a thumbs up. Also, if there are any questions on this problem, let me know.
Susan C.