Write an equation in standard form of the line that passes through the point (6, -4) and has slope 1/2 .

Question

I really need understanding someone please help.

Answer 1

The Standard Form for a linear equation is Ax + By = C (A ≥ 0)

Because we have coordinates of a point on the line and slope, let's use Point-Slope Form of linear equation

y - y₁ = m(x -x₁)

y - (- 4) = (1/2)(x - 6) 

y + 4 = (1/2)x - 3

y - (1/2)x = - 3 - 4

Let's multiply both sides of equation by (- 2)

x - 2y = 14

~~~~~~~~~
6 - 2*(- 4) = 14
6 + 8 = 14
   14 = 14

Answer 2

Hi Summer;

This is standard form equation for a line...

y=mx+b

m=slope..This is (y₂-y₁)/(x₂-x₁)--The change of y divided by the change of x.  Some will call it rise over run.

b=y-intercept.  This is the value of y when x=0.

 

y=mx+b

y=(1/2)x+b

 

Let's plug-in the one point provided...

-4=(1/2)(6)+b

-4=3+b

Let's subtract 3 from both sides to isolate b...

-3-4=3+b-3

-7=b

 

y=(1/2)x-7

 

I hope this helps.  If not, please let me know.

Answer 3

y=mx +b where m is given at 1/2

 

substitute the point (6,-4)

 

-4= (1/2)6 +b

-4=3+b

b=-7

Equation would be y=1/2x -7