I really need understanding someone please help.

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Because we have coordinates of a point on the line and slope, let's use Point-Slope Form of linear equation

y - y

y - (- 4) = (1/2)(x - 6)

y + 4 = (1/2)x - 3

y - (1/2)x = - 3 - 4

Let's multiply both sides of equation by (- 2)

~~~~~~~~~

6 - 2*(- 4) = 14

6 + 8 = 14

14 = 14

*for a linear equation is***Standard Form***(A ≥ 0)***Ax + By = C**Because we have coordinates of a point on the line and slope, let's use Point-Slope Form of linear equation

y - y

_{1}= m(x -x_{1})y - (- 4) = (1/2)(x - 6)

y + 4 = (1/2)x - 3

y - (1/2)x = - 3 - 4

Let's multiply both sides of equation by (- 2)

**x - 2y = 14**~~~~~~~~~

6 - 2*(- 4) = 14

6 + 8 = 14

14 = 14

## Comments

standard formatthe instructor is looking for. The format David and I used is calledslope-intercept. You also used thepoint-slope format.