write an equation of a line that passes through (-2,-4) and is perpendicular to the line y=1/2x+3

Question

write an equation of a line that passes through (-2,-4) and is perpendicular to the line y=1/2x+3

Answer 1

To be perpendicular to y=1/2x+3,

the slope has to be -2, since the product of the slopes of 2 perpendicular lines is -1.

Then it is y=-2x+K passes througn (-2, -4).

plug in the point:

-4 =-2*(-2) +k

k=-8

so y =-2x-8 is the line.