(2,8) (0,-8)

Question

i need this in stnderd form 

Answer 1

The slope of a line is m=(y₃-y₁)/(x₂-x₁) = (-8-8)/(0-2) = 8

The slope also is m=(y-y₁)/(x-x₁), which, in Standard Form is  mx-y = mx₁-y₁

Using the slope m=8 and the point (2,8):

      8x - y = 8(2) -8

      8x - y = 8

Answer 2

First, we know that -8 is the y-intercept (or b).

 

Second, let's find the slope (or rise-over-run), which is m = (y2 - y1) / (x2 - x1).

m = (-8 - 8) / (0 - 2)

m = (-16) / (-2) = 16/2 = 8

 

Third, we can create an equation in slope-intercept form.

y = mx+b

y = 8x - 8

 

Fourth, we can start converting this into standard form, which only contains positive integers.

y = 8x - 8

Subtract by 8x on both sides.

-8x + y = -8

 

Technically, the co-efficient of x shouldn't be negative in true standard form, so we will multiply both side by -1.

(-1) (-8x + y) = (-1) (-8)

Use the distributive property.

(-1)(-8x) + (-1)(y) = 8

8x - y = 8

Answer 3

(2,8) (0,-8)

y2-y1/x2-x1=8-(-8)/2-0

m=16/2=8

y=8x+b

8=8(2)+b

b=-8

y=8x-8

standard form is

8x-y=8