
Barry S. answered 11/07/15
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Each term in the sequence can be represented by:
A(n) = 4n-3
So, A(15) = 4(15) - 3 = 57
Checking:
1, 5, 9, 13, 17, 21, 25, 29, 33, 37, 41, 45, 49, 53, 57
Sum:
(A1 + An)*n/2
Substituting:
(1 + 57) * 15/2
(58)*15/2
29 * 15
435.