A company with loud machinery needs to cut its sound intensity to 37% of its original level. By how many decibels would the loudness be reduced? Use the L = 10

Question

A company with loud machinery needs to cut its sound intensity to 37% of its original level. By how many decibels would the loudness be reduced? Use the L = 10 log I/I. Round to the nearest hundredth.

Answer 1

Maybe?

 

ß₁ = 10 log I₁/I₀     ß2 = 10 log I₂/I₀

 

ß1 - ß2 = 10 log I₂/I₁  = 10 log 2 = 3 dB. Thus when intensity doubles, intensity level changes by 3 dB

 

So:

10 log 1.63 = 2.12 dB