the sum of 3 consecutive even integers is 612. find the integers

Question

im stuck with this math word problem 

Answer 1

Let the 1st integer = x

Let the 2nd integer = x + 2

Let the 3rd integer = x + 4

 

 

Using these variables, we can set an equation to represent the sum of the intergers.

 

x + (x + 2) + (x + 4) = 612

 

 

Solve for x from the equation.

 

3x + 6 = 612

 

 

Subtract 6 on both sides of equation.

 

3x = 606

 

 

Divide both sides of equation by 3.

 

x = 202

 

 

Finally, substitute this value of x back into the variables to get your integers.

Answer 2

Let the number be x, then the numbers are (x), (x+2), (x+4)

Given that 

(x)+(x+2)+(x+4)=6123x=612-6

3x+6=612

3x=612-6

x=606/3=202

The numbers are

202, 204, 206