Don L. answered 10/21/15
Tutor
5
(18)
Fifteen years teaching and tutoring basic math skills and algebra
Shara, set this up as two linear equations.
Equation 1: Eric has 130 coins consisting of quarters and nickels. Let Q represent the quarters and N represent the nickels, than the equation is:
Q + N = 130
Equation 2: The total value of all of the coins is 15.90. Each quarter represents .25 and each nickel represents .05, then the second equation is:
.25Q + .05N = 15.90
I prefer not to work with fractions or decimals, therefore, multiple equation 2 by 100. This gives:
25Q + 5N = 1590
Now we can solve for Q and N:
Q + N = 130
25Q + 5N = 1590
Multiply equation 1 by -5 and add them together:
-5Q - 5N = -650
25Q + 5N = 1590
-------------------------
20Q = 940
Divide both sides by 20 to get the value of Q:
Q = 47
Substitute for Q in one of the original equations to get the value for N
Q + N = 130
47 + N = 130
Subtract 47 from both sides to find the value of N:
47 - 47 + N = 130 - 47
N = 83
Check the answers by replacing Q and N is the second equation
.25Q + .05N + 15.90
.25(47) + .05(83) = 15.90
11.75 + 4.15 = 15.90
15.90 = 15.90, values check.
Questions?