
Mark M. answered 10/15/15
Tutor
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Mathematics Teacher - NCLB Highly Qualified
A = a0(0.5)t/h, where a0 = starting amount, h = half life, t = time
0.25a0 = a0(0.5)t/37
0.25 = (0.5)t/37
ln 0.25 = (t/37) ln 0.5
-1.38629436 ≈ (t/37) (-0.693147181)
2= t/37
74 = t
The sample is good for 74 years.
Or, without all the Algebra.
After 37 years 50% is left. After another 37 years 25% is left. So the sample is good for 74 years.
Sometimes understanding what is going on in the problem and thinking is faster than Algebra!