Find the slope -intercept form of the equation of a line that passes through the given points. (6,-9),(-2,3)

I solved it and this is what I got -12/8=1.5

If I am wrong let me know and tell me the steps and solved it for me

Find the slope -intercept form of the equation of a line that passes through the given points. (6,-9),(-2,3)

I solved it and this is what I got -12/8=1.5

If I am wrong let me know and tell me the steps and solved it for me

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Merrick, NY

First thing you have to do is get the slope

(y2-y1)/(x2-x1) = slope

lets make (6,-9) point 1, and (-2,3) point 2 you dont really need to do this part but it helps

so x1 = 6 y1 = -9 x2 = -2 y2 =3

(3 - -9)/(-2 - 6) = 12/-8 or -3/2

now the Point-Slope Equation of a Line is y - y1 = m(x - x1)

so lets plug in

Y - -9 = (-3/2)(X - 6) or

Y +9 = (-3/2)(X-6)

Palatine, IL

what you have found is correct but i think you accidentally lost your sign

-12/8 is correct which will simplify as -3/2 or -1.5 .

Next you will have to write out the slope intercept form equation

Y = MX + b Now plug in the order pair (either one) into X and Y. I picked (-2,3)

3 = (-3/2)*(-2) + b

3 = 3 + b now solve for b by subtracting 3 on both side of the equal side

0 = b

Therefore Equation will be: Y= -3X/2 + 0 Or Y=-3X/2

I hope this helps!

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