HELP ME OUT PLEASE SOLVE IT..............

Question

Find the slope -intercept form of the equation of a line that passes through the given points. (6,-9),(-2,3)

 

 

 

I solved it and this is what I got -12/8=1.5

 

 

If I am wrong let me know and tell me the steps and solved it for me 

Answer 1

First thing you have to do is get the slope

 

(y2-y1)/(x2-x1) = slope

 

lets make (6,-9) point 1, and (-2,3) point 2      you dont really need to do this part but it helps

so x1 = 6  y1 = -9                  x2 = -2  y2 =3

 

(3 - -9)/(-2 - 6) = 12/-8 or -3/2

 

now the Point-Slope Equation of a Line is y - y1 = m(x - x1)

 

so lets plug in 

Y - -9 = (-3/2)(X - 6) or

 

Y +9 = (-3/2)(X-6)

Answer 2

what you have found is correct but i think you accidentally lost your sign

 

-12/8 is correct which will simplify as -3/2  or -1.5 .

 

Next you will have to write out the slope intercept form equation

 

Y = MX + b   Now plug in the order pair (either one) into X and Y.  I picked (-2,3)

3 = (-3/2)*(-2) + b

3 = 3 + b  now solve for b by subtracting 3 on both side of the equal side

0 = b

 

Therefore Equation will be: Y= -3X/2 + 0  Or Y=-3X/2

 

I hope this helps!