I need help ASAP please,

Question

I cant figure this problem out . Find an equation of the line containing the given pair of points (-5,-3)an(-9,-8) PLEASE HELP

Answer 1

Since 2 points are given we can use 2 points form directly here.

 

the points are (-5,-3) and (-9,-8)

 

The 2 points form is : (y-y1) = (y2 - y1)/(x2-x1) * (x - x1)

 

y + 3 = (-8+3)/(-9+5) * (x + 5)

 

y+3 = -5/(-4) * (x+5)

 

4(y+3) = 5(x+5)

 

4y + 12 = 5x + 25

 

5x - 4y = -13

Answer 2

find the slope of the line = delta y/delta x = (-8+3)/(-9+5) = 5/4

the equation of a straight line is in general y = mx +6

substitute (-5, -3) into this to find b

that is: -3 = (5/4)*(-5) + n

-3 = -24/4 + b

b = 13/4

thuse the line is 

y = 5x/4 + 13/4

 

Answer 3

An equation of the line is y = mx + b, where m is the slope and (0,b) is the y-intercept.  

 

m = [-8-(-3)]/[-9-(-5)] = -5/(-4) = 5/4

 

So, y = (5/4)x + b

 

Since (-5, -3) is a point on the line, -3 = (5/4)(-5) + b

 

                                                              -3 = -25/4 + b

 

                                                               b = 25/4 - (3) = 13/4

 

Equation of line:  y = (5/4)x + (13/4)

 

Another form of the equation:  multiply by 4 to get 4y = 5x + 13

 

So, 5x - 4y = -13