
Dom V. answered 09/28/15
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Cornell Engineering grad specializing in advanced math subjects
I'm guessing the m2 mass is allowed to fall from rest, and that motion is what drags the glider along the track (if that's not the case, I'm afraid I'll need more information to solve part a of the problem).
(a) If m2 is falling from rest, it is only subject to gravitational acceleration g. m1 is being pulled along at the same rate due to the string, so its acceleration should have the same magnitude. The acceleration vectors would be
- a1 = 9.8 m/s2 oriented along the table (i.e. to the left or right)
- a2 = 9.8 m/s2 oriented down
(b) We know from Newton's 2nd law that F=ma. If we graph force as a function of acceleration, where y=F and x=a, we would get a linear graph with a slope of m, the mass in question.