what is 14n+2-7n=38

Question

i need help

 

Answer 1

Hi Rajendra;

14n+2-7n=38

 

You need to first organize the equation.

Combine the n's...

14n-7n

 

Then, move the 2 from the left side to the right.  It is initially an added number.  It becomes subtracted.

 

14n-7n=38-2

 

The equation is now...

 

7n=36

 

Move the 7 from the left side to the right.  It is initially multiplied.  After it moves, it is divided.

 

n=36/7

 

Note the fact that the n, which is the unknown factor, is now on the left side, completely isolated.  This is the protocol.  It should not be on the right.

 

n=5.14

 

Do the instructions explain how many digits to the right of the decimal are required?

Answer 2

In an algebraic expression like ax^y, where "a" is a coefficient, "x" is a base (or variable in this particular case), and "y" is an index. Addition  (subtraction) of the expressions is done by adding (subtracting) only the coefficients and other parts remains intact if the bases and indices are equal. So, in this problem we will subtract 7 from 14 and will be 7n. And other follows as the previous friends have suggested. 

FYI, if you multiply (divide) your expressions you will add (subtract) the indices and multiply (divide) coefficients if the bases are same. Also please note that there is always coefficient 1 and index 1 if we just see x as an expression.

Answer 3

Combine the same terms. 14n - 7n= 7n.

The equation becomes 7n+2=38.

Subtract 2 from each side. 7n+2-2=38-2.

The equation becomes 7n=36.

Divide each side by 7 to get n on its own. 7n/7 = 36

Finally, n=5 & 1/7 or 5.142857

Best of luck!

Answer 4

You need to combine like terms. So, 14n-7n= 7n. So, now, your equation is now 7n+2=38. Next, you need to subtract the two from each side. So 7n+2-2=38-2. Now you have 7n=36. Now, you need to divide each side by 7. So now, you have n=5 1/7