
Nataliya D. answered 09/02/13
Tutor
New to Wyzant
Patient and effective tutor for your most difficult subject.
ax2 + bx + c = 0
D = b2 - 4ac
x12 = (- b ± √D) / 2a
~~~~~~~~~~~
7 5
---- − ---- − 13 = 10
x2 x
( x ≠ 0 )
7 5
x2 • ---- − x2 • ---- − 13x2 = 10x2
x2 x
7 − 5x − 13x2 − 10x2 = 0
- 23x2 − 5x + 7 = 0
23x2 + 5x − 7 = 0
D = 52 − 4 • (- 7) = 25 + 28 = 53
x1 = (- 5 + √53) / 46 ≈ 0.05
x2 = (- 5 − √53) / 46 ≈ - 0.267
D = b2 - 4ac
x12 = (- b ± √D) / 2a
~~~~~~~~~~~
7 5
---- − ---- − 13 = 10
x2 x
( x ≠ 0 )
7 5
x2 • ---- − x2 • ---- − 13x2 = 10x2
x2 x
7 − 5x − 13x2 − 10x2 = 0
- 23x2 − 5x + 7 = 0
23x2 + 5x − 7 = 0
D = 52 − 4 • (- 7) = 25 + 28 = 53
x1 = (- 5 + √53) / 46 ≈ 0.05
x2 = (- 5 − √53) / 46 ≈ - 0.267