r=2; (h,k)=(0,2)
A circle centered at (h, k) with radius "r" is given by
(x - h)^{2} + (y - k)^{2} = r^{2}
~~~~~~~~~~~^{
}
Here h = 0 , k = 2, r = 2
Thus,
(x – 0)^{2} + (y – 2)^{2} = 2^{2}
Or
x^{2} + (y – 2)^{2} = 4
r=2; (h,k)=(0,2)
A circle centered at (h, k) with radius "r" is given by
(x - h)^{2} + (y - k)^{2} = r^{2}
~~~~~~~~~~~^{
}
Here h = 0 , k = 2, r = 2
Thus,
(x – 0)^{2} + (y – 2)^{2} = 2^{2}
Or
x^{2} + (y – 2)^{2} = 4