If the perimeter (p) is 144 length (l) is 41in then find Width (w)

Question

Answer 

Answer 1

p = 2(l + w) for rectangles

 

144 = 2(41 + w)

 

      = 82 + 2w

 

144 - 82 = 2w

 

(144 - 82)/2 = w = 28

 

To check:

 

144 = 88 + 2(28)

 

      = 88 + 56 = 144

Answer 2

Since we have length and width, this is a rectangle.  The perimeter of a rectangle is the sum of twice the length and twice the width. 

 

p = 2l + 2w

 

 

The perimeter and length are known.  Plug in the numbers into the formula.

 

144 = 2(41) + 2w

 

 

We now have an equation.  Solve for w to find the width.