
Mark M. answered 07/22/15
Tutor
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Mathematics Teacher - NCLB Highly Qualified
c = speed of car
0.625c = speed of bus
(1.5)(0.625)c = speed of train
t = d / r
240 / 0.9375c = time of the train
80 / c = time for the car
125 / 0.625c = time for bus
240 / 0.9375c + 80 / c + 125 / 0.625c = 11 Multiply both sides by "c"
240/0.9375 + 80 + 125/0.625 = 11c
256 + 80 + 200 = 11c
536 = 11c
Up to here the numbers come out neatly. Is "11" the correct number of hours?
What do you mean my "conventional" and "short-cut?"