slope-intercept (-2,-5) perpendicular to line x-2y=3

Question

Slope-intercept equation of line containing points (-2,-5) perpendicular to the line x-2y=3

Answer 1

If x - 2y = 3, then -2y = -x + 3

 

So, y = (1/2)x - 3/2

 

The slope of the line is 1/2.

 

The slopes of perpendicular lines are negative reciprocals.  

 

So, the slope of any line perpendicular to the given line is -2.

 

Equation of line with slope -2 and which goes through the point   (-2, -5) is:

 

                   y - (-5) = -2[x - (-2)]

 

                   y + 5 = -2x - 4

 

                         y = -2x - 9