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Jake P.

asked • 07/10/15

Solve this as soon as possible

Rectangle A has a length of 6 inches and a width of 4 inches. Rectangle A has the same area as rectangle B, but has different dimensions. The width of rectangle B is 10% shorter than the width of Rectangle A as shown.



Which percent represents how much longer the length of Rectangle B must be to maintain the same area as Rectangle A?


It must be 4% longer than Rectangle A.


It must be 8% longer than Rectangle A.


It must be 10% longer than Rectangle A.


It must be 11 1/9% longer than Rectangle A.

2 Answers By Expert Tutors

By:

David W. answered • 07/11/15

Tutor
4.5 (50)

Experienced Prof

Jake P.

your answer is wrong...
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07/11/15

David W.

tutor
Your comment puzzles me.  The answer I gave is, " Lb must be 11 1/9% longer than La" and is the same answer as Andrew gave:  "The answer from the choices will be 11 1/9."
 
Also, the process is better --  there was no rounding and the unnecessary (TMI) calculations were excluded.  Further, I included wise advice for approaching a problem and understanding distractors (wrong answers).
 
Thus, your statements are misguided.  You may have any expert read and analyze these posts -- if they know what they are talking about, they will agree.
 
Best wishes anyway!!
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07/11/15

Andrew M. answered • 07/10/15

Tutor
New to Wyzant

Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

Jake P.

your answer is correct
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07/11/15

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