Help me please this is so hard

Is it (7/2)X - 1 = 2X + 5 or is it 7/(2X) - 1 = 2X + 5? The formatting makes it a bit unclear.

But assuming it is (7/2)x-1=2x+5...

For this one, let's first add 1 to both sides to isolate X on the left hand side.

7/2x - 1 + 1 = 2X + 5 + 1

Gives you 7/2X = 2X + 6

Now subtract 2X from both sides to get X's on the left side and numbers on the right side.

7/2X - 2X = 2X -2X + 6

7/2X - 2X = 6

Find a common denominator for 7/2X - 2X

7/2X - 4/2X = 6

3/2X = 6

Multiply both sides by 2 to cancel out the fraction

3/2X = 6

3X = 12

Now divide by 3.

3X = 12

X = 4

Assuming it is 7/(2X) - 1 = 2X + 5

First add 1 to both sides

7/(2X) - 1 +1 = 2X + 5 + 1

7/(2X) = 2X + 6

Multiply both sides by 2X

7/(2X) = 2X + 6

7 = 4X^2 + 12X

Subtract 7 from both sides

4X^2 + 12X - 7 = 0

Use Quadratic formula

Gives you X = .5 or -3.5