Probability?

Question

1.In a game of dice, the probability of rolling a 12 is 1/36. The probability of rolling a 9, 10, or 11 is 9/36. The probability of rolling any other number is 26/36. If the player rolls a 12, the player wins $8. If the player rolls a 9, 10, or 11, the player wins $2. If the game is fair, how much should the player lose when the player rolls any number less than 9?

 

2.In a certain game, the probability of winning is 0.2, and the probability of losing is 0.8. If the player loses, the player will lose $5. If the game is fair, how much does the player collect when the player wins?

Answer 1

the probability of winning times the amount won = the probability of losing time s the amount lost.  

1/36  x 8 = 8/36

9/36  x 2 = 18/36

total = 26/36

 

so 26/36 x ? = -26/36

 

Answer Should lose $1

 

Part 2

.2 * x =.8 * 5

 

x = 20

 

The winner should get $20