
Hugh B. answered 06/16/15
Tutor
4.9
(36)
Statistical applications in Stata
Hi Jack,
1.
Probability Table for payoff from one ticket
Outcome Probability Expected payoff (= outcome x probability of outcome)
0 2996/3000 0
100 1/3000 100/3000 = 1/30
500 1/3000 500/3000 = 1/6
1000 1/3000 1000/3000 = 1/3
1500 1/3000 1500/3000 = ½
Expected payoff = 1/30 + 1/6 + 1/3 + ½ = 31/30 ≈ 1.03
No, I would not buy because the game has an expected payoff of about $1.03 for a $5 ticket.
2.
There are 36 possible outcomes, 6 possible outcomes on the first roll and for each of those 6 outcomes, 6 possible outcomes on the second roll. Each of these outcomes is equally likely, so we will enumerate the number of ways a total of 7 can be made for the 2 rolls:
First roll Second roll
1 6
6 1
2 5
5 2
3 4
4 3
From the six possible ways to make a 7 as the sum of two rolls, we know the probability of making a 7 as the sum of two rolls is 6/36 = 1/6. With a probability of 5/6, some other outcome that does not add up to 7 is obtained. The payoff is 0 for the outcomes not equal to 7 and 10 for the outcome that the rolls add to 7, so the expected outcomes is
(5/6 x 0) + (10 x 1/6) = 10/6 ≈$1.67
No, I would not play this game because it costs $10 and has an average payout of $1.67.
3.
We need to know the probability of drawing a heart and the probability of drawing a face card that is not a heart. Each draw is equally likely and there are 13 hearts and 52 cards in a deck, so the probability of a heart is 13/52 = ¼. There are 12 face cards in the deck but only 9 face cards that are not hearts and so 9/52 chance of getting a face card that is not a heart. The rest of the outcomes that pay -15 eat up the rest of the probability, 30/52. Therefore the expected payoff off the game is
(¼ x 10) + (9/52 x 8) + (30/52 x -15) ≈ -$4.77
No, I would not play this game because the expected payoff is a loss of about $4.77.
Hope this helps, feel free to ask questions.
Kind regards,
Hugh
1.
Probability Table for payoff from one ticket
Outcome Probability Expected payoff (= outcome x probability of outcome)
0 2996/3000 0
100 1/3000 100/3000 = 1/30
500 1/3000 500/3000 = 1/6
1000 1/3000 1000/3000 = 1/3
1500 1/3000 1500/3000 = ½
Expected payoff = 1/30 + 1/6 + 1/3 + ½ = 31/30 ≈ 1.03
No, I would not buy because the game has an expected payoff of about $1.03 for a $5 ticket.
2.
There are 36 possible outcomes, 6 possible outcomes on the first roll and for each of those 6 outcomes, 6 possible outcomes on the second roll. Each of these outcomes is equally likely, so we will enumerate the number of ways a total of 7 can be made for the 2 rolls:
First roll Second roll
1 6
6 1
2 5
5 2
3 4
4 3
From the six possible ways to make a 7 as the sum of two rolls, we know the probability of making a 7 as the sum of two rolls is 6/36 = 1/6. With a probability of 5/6, some other outcome that does not add up to 7 is obtained. The payoff is 0 for the outcomes not equal to 7 and 10 for the outcome that the rolls add to 7, so the expected outcomes is
(5/6 x 0) + (10 x 1/6) = 10/6 ≈$1.67
No, I would not play this game because it costs $10 and has an average payout of $1.67.
3.
We need to know the probability of drawing a heart and the probability of drawing a face card that is not a heart. Each draw is equally likely and there are 13 hearts and 52 cards in a deck, so the probability of a heart is 13/52 = ¼. There are 12 face cards in the deck but only 9 face cards that are not hearts and so 9/52 chance of getting a face card that is not a heart. The rest of the outcomes that pay -15 eat up the rest of the probability, 30/52. Therefore the expected payoff off the game is
(¼ x 10) + (9/52 x 8) + (30/52 x -15) ≈ -$4.77
No, I would not play this game because the expected payoff is a loss of about $4.77.
Hope this helps, feel free to ask questions.
Kind regards,
Hugh
Jack H.
06/16/15