A camel can drink 15 gallons of water in 10 minutes. At this rate, how much water can the camel drink in

Question

I need tHE ANSWER PLEASE

Answer 1

The “proportions” class of word problems often give rates.

In this problem, you may state the constant rate (“at this rate”) in units of either gallons per minute or else minutes per gallon.  Whichever you choose, it is constant.

For this problem, the output variable, “how much water?” is sought. There usually is an input value, such as “in 15 minutes.”

So, let’s create a formula using: 
                     input variable T = new number of minutes
                     output variable W = new gallons of water

The proportion can be either:
                 15 gallons / 10 minutes             or 10 minutes / 15 gallons

Since the output is in gallons, let’s use the first one (to keep W in the numerator) and set the old and new rates equal (“at this rate”):
                  15 / 10  =  W / T
                     W = 1.5 T           (switching sides, multiplying both sides by T and reducing fraction)

Now, if the problem specifies a T, just plug it in and complete the computation.

Answer 2

This is shaping up to be a proportion problem, which will go something like this:

 

   15 gal        x gal

   --------  =  --------

   10 min       # of minutes given in problem, directly or indirectly (1.5 hours would have to be converted to 90 minutes)

 

Cross-multiply to get:

    

    15# = 10x , so # = 10x        or # = 2x/3

                                 -----

                                  15