Rearranging formulae:

Question

Make x the subject of these equations:
1) 3x-w=vx+y
2) 8-wx=vx+5
3) 5(wx-v)=7(x+v)
4) y=x/x-7
5) y=x+7/x-5
6) y=a-9x/bx+8

Answer 1

I'll assume you want to solve for x in each of these equations. In general, you'll want to arrange the equation so that every term with x in it is on one side and every other term is on the other side. Then, factor x out of one side and divide by whatever remains.

 

 

 

Here are a few as examples:

 

 

 

1)

 

3x - w = vx + y

3x = vx + y + w

3x - vx = y + w

x(3 - v) = y + w

x = (y + w)/(3 - v)

 

 

 

3) (Did you mean for one v to be a y?)

 

5(wx - v) = 7(x + v)

5wx - 5v = 7x + 7v

5wx = 7x + 7v + 5v

5wx - 7x = 7v + 5v

x(5w - 7) = 12v

x = (12v)/(5w - 7)

 

 

 

5) (Did you mean to put parentheses around a - 9x and bx + 8?)

 

y = (a - 9x)/(bx + 8)

y(bx + 8) = a - 9x

bxy + 8y = a - 9x

bxy = a - 9x - 8y

bxy + 9x = a - 8y

x(by + 9) = a - 8y

x = (a - 8y)/(by + 9)