
David W. answered 05/13/15
Tutor
4.7
(90)
Experienced Prof
This statistics question tests whether you can do percents (math) and understand “selecting an audience member at random.”
Let’s consider the “full house” (every seat filled) on the opening night of The Lion King:
The number of programs sold is:
0.40 * 800 = 320 (balcony)
0.50 * 1200 = 600 (main floor)
So, of the 2000 seats total, 920 bought programs.
If it is equally likely that we select any one of the 2000 patrons (could have a seat anywhere), then we have a 920 in 2000 chance of selecting a person who has bought a program.
920 / 2000 = 0.46 or 46% probability that we select a person who bought a program
Let’s consider the “full house” (every seat filled) on the opening night of The Lion King:
The number of programs sold is:
0.40 * 800 = 320 (balcony)
0.50 * 1200 = 600 (main floor)
So, of the 2000 seats total, 920 bought programs.
If it is equally likely that we select any one of the 2000 patrons (could have a seat anywhere), then we have a 920 in 2000 chance of selecting a person who has bought a program.
920 / 2000 = 0.46 or 46% probability that we select a person who bought a program