Nikita D. answered 04/25/15
Tutor
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Biology graduate Specializing in Science and Math Coursework
Hey Jessica,
To solve this problem, we need to use what we know about the sides of right triangles. We know that c2=a2+b2
In this case, a=a and b=a+3 and c=√64. The equation will then look something like this:
(√64)2=a2+(a+3)2
This simplifies to
64=a2+(a2+6a+9)
64=2a2+6a+9
Now, to solve for a, we'll need to use the dreaded quadratic formula. To get the equation into that format, we'll subtract 64 from both sides and factor out the 2. That gives us:
0=a2+3a-28
Plugging that in the quadratic formula will look like this:
(-3+/- √(32-(4)(1)(-28)))/2
(-3+/- √9+112)/2
(-3+/-√121)/2
(-3+/-11)/2
8/2 or -14/2
that gives us a=4 or -7. Since the length can't be negative, we know a=4 and b=4+3=7
Hope that helps,
Nikita