Arthur D. answered 04/23/15
Tutor
4.9
(338)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
3x^3-11x^2-6x+8=0
using trial and error with factors of 8 (1,-1,2,-2,4,-4,8,-8)...
-1 is a solution
therefore (3x^3-11x^2-6x+8)/(x+1)=3x^2-14x+8
3x^2-14x+8=0
(3x-2)(x-4)=0
3x-2=0
3x=2
x=2/3
x-4=0
x=4
-1,2/3,4