Nathan B. answered 04/22/15
Tutor
5
(20)
Elementary and Algebraic skilled
This sounds like a Pythagorean problem. Let's write down what we know:
a2 + b2 = c2 where a is the pole length, b is the length along the ground, and c is the wire
c = a + 3
b= a - 3
Since we have values for b and c, let's put them into our equation:
a2 + (a - 3)2 = (a + 3)2
Multiply out:
a2 + a2 - 6a + 9 = a2 + 6a + 9
Now we start moving everything to one side. one of the a2 cancel out:
a2 - 6a +9 = 6a + 9
And the 9s cancel out:
a2 - 6a = 6a
Move the 6a over as well:
a2 - 12a = 0
Now we can factor:
a(a - 12) = 0
a = 0, 12
We can't have a length of 0, so the a-value has to be 12:
c = 12 + 3
c = 15
b = 12 - 3
b = 9
Now let's check:
122 + 92 = 152
144 + 81 = 225
225 = 225