Create a line perpendicular to the line that goes between the points (-7,0) and (0,13)

Create a line perpendicular to the line that goes between the points (-7,0) and (0,13)

How do I find an equation based on that information

I JUST NEED HELP

How do you solve this? Directions: Write an equation of the line that passes through the given point and is parallel to the given line. Questions: 1. (1,7), -6x + y...

Find the equation of the line perpendicular to 4x+32y=128 and going through the point (-7,-4). Write your answer form y=mx+b

(0,6) and (7,10) (3,-10) and (10,-6)

Write an equation of the line satisfying given conditions. Write the answer in slope intercept or standard form. Express numbers as integers or simplified fractions.

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Perpendicular lines

(2,-1);y=-2x +1

please.help. im clueless

It is asking where the perpendicular line can bisect in a triangle.. The given options are inside the triangle, on the triangle, or outside of the triangle.

Exampl; (2,-1) y=-2x+1

I need the answer to this problem.

i dont understand this question can you guys please help me.

Find the value of c for which the lines 5x+cy=9 and x-3y=9 are perpendicular

Please explain how you did it.

write the equation of the line through the given points perpendicular to the given line

A line contains the points (-1,1) and (5,4) The slope is 1/2 The equation of the line in point-slope form is: (y-1) = 1/2(x- -1) The equation of the line in slope-intercept form is: y...

Through: (4, 2), perp. to y = -4/3x – 4