x^2 + 11x - 12 = 0 #solve the equation by using quadratic formula. #Write imaginary solutions in the form a + bi.

x^2 + 11x - 12 = 0 #solve the equation by using quadratic formula. #Write imaginary solutions in the form a + bi.

a) write an equation that models the number of magazines that john can afford. b)solve the equation.

If the perimeter is 24 meters, calculate the value of x. - one of the short sides is 3x-2. -one of the long sides is 4x.

-The largest angle is 12 times the smallest angle -The middle angle is 5 times the smallest angle Find the measures of the angles. Provide a step-by-step discussion regarding how you would...

x^2 + 11x - 12 = 0 #solve the equation by using quadratic formula. #Write imaginary solutions in the form a + bi.

Please help!!!

Part 1) Please solve each equation in order to get the height for each one. h(0)=-16t2+528t-1440 h(5)=-16t2+528t-1440 h(15)=-16t2+528t-1440 h(25)=-16t2+528t-1440 h(35)=-16t2+528t-1440 Part...

solve ~ 10 + 5x= 8x + 14

According to the U.S. census bureau survey in 2009 about half as many people in the United States spoke Vietnamese at home as spoke Chinese. If a total of about 3900000 people spoke these languages...

Part 1 of 3: A A missile is shot upward from a submarine 1440 feet below sea level at an initial velocity of 528 ft/sec. A function that approximates the height of the missile (relative to...

I need an algebraic equation. No need for an explanation, all I need in the equation. Nothing else.

Why does x0=1 for any x where x≠0?

I need an algebraic equation. No need for an explanation, all I need in the equation. Nothing else.

Applying equations and inequalities

I just need an answer to see if I'm correct. Thank you

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25p^2 - 10p = 2 #solve the quadratic equation by completing the square and applying the square root property

2a^2 + 4a + 5 = 0 #solve the quadratic equation by completing the square and applying the square root property

HELP!!! please explain how to find this please!

this problem is a problem that i am having trouble with

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