How to find the dimension of the box in algebraic expression

Question

How to find the dimension of the box in algebraic if its volume is 9x³-x?

Answer 1

9x^3 - x

= x(9x^2 -1) = x(3x+1)(3x-1) = Volume = V = LWH, L=length, W=Width, H=Height of the box

so odds are the dimensions you want are

x by 3x+1 by 3x-1 whre x > 1/3