n=324
j = 2n/3
j+20 = (4/5)(n-29)) multiply by 5
5j + 100 = 4n -116
5(2n/3) + 100 =4n -116
10n/3 = 4n -216, multiply by 3
10n = 12n -648
2n =648
n = 324
n=324
j = 2n/3
j+20 = (4/5)(n-29)) multiply by 5
5j + 100 = 4n -116
5(2n/3) + 100 =4n -116
10n/3 = 4n -216, multiply by 3
10n = 12n -648
2n =648
n = 324
Grayson S. answered 05/27/25
Undergraduate Mechanical Engineering Student at Purdue University
Mark M. answered 05/27/25
Mathematics Teacher - NCLB Highly Qualified
Samantha A. answered 05/27/25
96th Percentile in SAT Math (2022); STEM-Focused Cornell Undergraduate
Hi! For this problem, I’ll guide you through an efficient process that can be followed to work through the problem step-by-step through substitution and solving for the unknown.
Provided Information:
Given:
Find:
How many game cards did Nat have at first?
Step 1: Define variables
Let:
From the problem, we know Joshua initially has 2/3 times as many cards as Nat. This means that, for any number of cards Nat has, Joshua will have 2/3 of that amount (Because 2/3 is less than 1, we can infer that Joshua begins with less cards than Nat).
Step 2: Express the situation after changes
After change #1 (Joshua buys 20 more cards):
After change #2 (Nat loses 29 cards):
Step 3: Use the new ratio given (4/5)
According to the problem, “After Joshua bought another 20 game cards and Nat lost 29 game cards, Joshua now has 4/5 as many game cards as Nat.” This tells us the new ratio between Joshua's and Nat’s card totals after the changes:
Step 5: Evaluate and solve the algebraic equation
Answer: Nat originally had 324 game cards at the start of the game.
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