Hi Madison,
This is like your Hitchhiker’s Guide problem, but with one key difference. We are interested in fewer than, not at most. It’s still a binomial distribution, so you can still use binomcdf, but we have to change n:
n = 112
p = 0.28
x = 18 (This is important. We need to subtract 1 from 19 since question asked specifically for fewer than.)
2nd-VARS-binomcdf(112, 0.28, 18) = 0.002
I hope this helps.