Display the computation needed to get 0.05M CaCl2?

Question

Display the computation needed to get 0.05M CaCl2.

Edited by drift hunters 1 day ago

Answer 1

The way to get 0.05 M CaCl₂ depends on what you start with. Are you staring with solid CaCl₂? Or a solution that is 0.5 M, 1.0 M, 0.2 M? Also, how much (what volume of the 0.05 M CaCl₂ do you want to make?

So, let's say you already have a 0.5 M solution, and you want to make 100 mls of 0.05 M solution. You can use V1M1 = V2M2 as follows:

(x ml)(0.5 M) = (100 ml)(0.05 M) and x = 10 mls. So use 10 mls of 0.5 M and dilute to a final volume of 100 mls to give you the 0.05 M CaCl₂ solution.

If you only have solid CaCl₂, then you proceed as follows. Assume you want to make 100 mls of 0.05 M CaCl₂.

The molar mass of CaCl₂ = 111 g / mole

0.05 M = 0.05 mol / L

0.05 mol / L x 111 g / mol = 5.55 g / L

5.55 g / L x 0.1 L = 0.555 g

Weigh out 0.56 g of CaCl₂ (anhydrous) and dissolve in sufficient water to make a final volume of 100 mls.

Answer 2

Display the computation needed to get 0.05M CaCl2?

How to solve the Problem:

How To make a 0.05 M solution of CaCl2 initiate the follow steps:

Step 1:

Know the molarity formula:

Molarity = Moles of solute / liters of solution

Step 2:

Calculate moles needed: for 1 Liter

Moles of CaCl2 = M × liters of solution Moles of CaCl2 = M x l liters of solution

Moles of CaCl2 = 0.05 M ×1 L= 0.05 moles of CaCl2 = 0.05M × 1L= 0.05 moles

Step 3:

Find the molar mass of CaCl2:

1. Calcium (Ca) = 40.08 grams divided by moles
2. Chlorine (Cl) = 35.45 grams divided by moles times 2 = 70.90 grams divided by moles
3. Total = 40.08 + 70.90 = 110.98 grams / moles = 110.98 grams divided by moles

Step 4:

Calculate grams needed:

Grams of CaCl2 = 0.05 moles x 110.98 grams divided by moles = 5.549 grams of CaCl2 = 5.55 grams

Step 5:

Combine all the ingredients (compounds):

1. Weigh out about 5.55 grams of CaCl2.
2. Dissolve it in a small amount of water.
3. Then, add more water until the total volume is 1 liter.

Final Solution: Now you have a 0.05 M solution of CaCl2 = 5.55 grams

I hope the mathematical calculations (step by step approach) was helpful. Please let me know if you require any more assistance. If anyone in my neighborhood is interested in setting up an in-person math tutoring session. I look forward to hearing from them. Have an amazing day. Doris H.