Let f(x)=x^2 and g(x)=2x^2-3x+2. What is the difference of the two functions, f(x)−g(x)

Answer 1

Hi Marzy,

f(x) - g(x) =

x^2 - (2x^2 - 3x + 2)

Distribute the negative:

x^2 - 2x^2 + 3x - 2

Combine like terms:

-x^2 + 3x - 2

I hope this helps.

Answer 2

For finding the difference between two functions, you need to plug in both equations into a larger equation where you are subtracting g(x) from f(x).

If f(x) = x^2 (underlined) and g(x) = 2x^2 - 3x + 2 (not underlined), then f(x) - g(x) is:

f(x) - g(x) = x^2 - (2x^2 - 3x +2)

You then distribute the negative throughout the entire g(x) equation:

f(x) - g(x) = x^2 - 2x^2 +3x - 2

And combine like terms to get the finished equation which is the difference between the two functions:

f(x) - g(x) = -x^2 + 3x - 2

Answer 3

See the videa.