limx→0- [f(x)] = limx→0- (2-x) = 2 - 0 = 2
limx→0+ [f(x)] = limx→0+(x+2) = 0 + 2 = 2
Since the one-sided limits are both equal to 2, limx→0 f(x) = 2.
Chance P.
asked 05/25/24How do I find the limit, if it exists, and how do I sketch its graph:
. 2-x, x≤0
lim f(x), where f(x) = {
x→0 . x+2, x>0
limx→0- [f(x)] = limx→0- (2-x) = 2 - 0 = 2
limx→0+ [f(x)] = limx→0+(x+2) = 0 + 2 = 2
Since the one-sided limits are both equal to 2, limx→0 f(x) = 2.
Raymond B. answered 05/25/24
Math, microeconomics or criminal justice
limit = 2 as x approaches 0
graph is a V shape of 2 staright perpendicular lines
meeting at the minimum point of the V, at (0,2)
the 2 lines are at angles 45 and 135 degrees with the horizontal
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